Arithmetic operations using switch case and do while loop in C Programming

A switch case is used to select one among multiple options.

Can we use arithmetic operators in switch case:

Yes, We Can use we. To provide symbols in a case statement a single quote is used.

To perform arithmetic operations, we create a case for each operator, for the matching operator, it will call the appropriate case statements and execute the statements.

In our program, we will use a switch case statement and do while loop statement

You can check both details here

algorithm for arithmetic operations using switch case in c

Lets see steps to write this C program

Declare variables
start loop
get num1 ,operator, num2 value from user
start switch case and pass operator in switch case
write the case for arithmetic operators and their associated statements
define default in switch case
Take input from the user to check loop continuity
if the user enters yes then repeat steps 2-7 else end the loop.

Fig: Arithmetic Operations Using Switch Case in C Programming

C program for arithmetic operations using switch case

#include<stdio.h>

int main() {
    int num1,num2;
    char c,ch;
    do{
       printf("\nEnter Num1 Operator [+,-,*,/] Num2 \n");
       scanf("%d %c %d",&num1,&c,&num2);

    switch(c){
        case '+':
                 printf("\n%d+%d=%d",num1,num2,num1+num2);
                 break;

        case '-':
                 printf("\n%d-%d=%d",num1,num2,num1-num2);
                 break;

        case '*':
                 printf("\n%d*%d=%d",num1,num2,num1*num2);
                 break;

        case '/':
                 printf("\n%d/%d=%f",num1,num2,(float)num1/num2);
                 break;

        default:
                 printf("\nEnter valid operation : +, -, *, /");
    }
    printf("\nEnter y to continue other character to end\n");
    getchar();
	scanf("%c",&ch);
    }while(ch=='y');
}

#include<stdio.h>

int main() {

int num1,num2;

char c,ch;

do{

printf("\nEnter Num1 Operator [+,-,*,/] Num2 \n");

scanf("%d %c %d",&num1,&c,&num2);

switch(c){

case '+':

printf("\n%d+%d=%d",num1,num2,num1+num2);

break;

case '-':

printf("\n%d-%d=%d",num1,num2,num1-num2);

break;

case '*':

printf("\n%d*%d=%d",num1,num2,num1*num2);

break;

case '/':

printf("\n%d/%d=%f",num1,num2,(float)num1/num2);

break;

default:

printf("\nEnter valid operation : +, -, *, /");

}

printf("\nEnter y to continue other character to end\n");

getchar();

scanf("%c",&ch);

}while(ch=='y');

}

Output

Enter Num1 Operator [+,-,*,/] Num2
2 + 2

2+2=4
Enter y to continue other character to end
y

Enter Num1 Operator [+,-,*,/] Num2
3 * 2

3*2=6
Enter y to continue other character to end
y

Enter Num1 Operator [+,-,*,/] Num2
 5 - 1

5-1=4
Enter y to continue other character to end
y

Enter Num1 Operator [+,-,*,/] Num2
5 / 6

5/6=0.833333
Enter y to continue other character to end
y

Enter Num1 Operator [+,-,*,/] Num2
1 + 2

1+2=3
Enter y to continue other character to end
n